Optimal. Leaf size=340 \[ \frac{b x (5 b c-a d)}{2 c d^2 \sqrt [4]{a+b x^2}}-\frac{\sqrt{a} \sqrt{b} \sqrt [4]{\frac{b x^2}{a}+1} (5 b c-a d) E\left (\left .\frac{1}{2} \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )\right |2\right )}{2 c d^2 \sqrt [4]{a+b x^2}}+\frac{\sqrt [4]{a} \sqrt{-\frac{b x^2}{a}} \sqrt{a d-b c} (2 a d+5 b c) \Pi \left (-\frac{\sqrt{a} \sqrt{d}}{\sqrt{a d-b c}};\left .\sin ^{-1}\left (\frac{\sqrt [4]{b x^2+a}}{\sqrt [4]{a}}\right )\right |-1\right )}{4 c d^{5/2} x}-\frac{\sqrt [4]{a} \sqrt{-\frac{b x^2}{a}} \sqrt{a d-b c} (2 a d+5 b c) \Pi \left (\frac{\sqrt{a} \sqrt{d}}{\sqrt{a d-b c}};\left .\sin ^{-1}\left (\frac{\sqrt [4]{b x^2+a}}{\sqrt [4]{a}}\right )\right |-1\right )}{4 c d^{5/2} x}-\frac{x \left (a+b x^2\right )^{3/4} (b c-a d)}{2 c d \left (c+d x^2\right )} \]
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Rubi [A] time = 0.294429, antiderivative size = 340, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.381, Rules used = {413, 530, 229, 227, 196, 399, 490, 1218} \[ \frac{b x (5 b c-a d)}{2 c d^2 \sqrt [4]{a+b x^2}}-\frac{\sqrt{a} \sqrt{b} \sqrt [4]{\frac{b x^2}{a}+1} (5 b c-a d) E\left (\left .\frac{1}{2} \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )\right |2\right )}{2 c d^2 \sqrt [4]{a+b x^2}}+\frac{\sqrt [4]{a} \sqrt{-\frac{b x^2}{a}} \sqrt{a d-b c} (2 a d+5 b c) \Pi \left (-\frac{\sqrt{a} \sqrt{d}}{\sqrt{a d-b c}};\left .\sin ^{-1}\left (\frac{\sqrt [4]{b x^2+a}}{\sqrt [4]{a}}\right )\right |-1\right )}{4 c d^{5/2} x}-\frac{\sqrt [4]{a} \sqrt{-\frac{b x^2}{a}} \sqrt{a d-b c} (2 a d+5 b c) \Pi \left (\frac{\sqrt{a} \sqrt{d}}{\sqrt{a d-b c}};\left .\sin ^{-1}\left (\frac{\sqrt [4]{b x^2+a}}{\sqrt [4]{a}}\right )\right |-1\right )}{4 c d^{5/2} x}-\frac{x \left (a+b x^2\right )^{3/4} (b c-a d)}{2 c d \left (c+d x^2\right )} \]
Antiderivative was successfully verified.
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Rule 413
Rule 530
Rule 229
Rule 227
Rule 196
Rule 399
Rule 490
Rule 1218
Rubi steps
\begin{align*} \int \frac{\left (a+b x^2\right )^{7/4}}{\left (c+d x^2\right )^2} \, dx &=-\frac{(b c-a d) x \left (a+b x^2\right )^{3/4}}{2 c d \left (c+d x^2\right )}+\frac{\int \frac{a (b c+a d)+\frac{1}{2} b (5 b c-a d) x^2}{\sqrt [4]{a+b x^2} \left (c+d x^2\right )} \, dx}{2 c d}\\ &=-\frac{(b c-a d) x \left (a+b x^2\right )^{3/4}}{2 c d \left (c+d x^2\right )}+\frac{(b (5 b c-a d)) \int \frac{1}{\sqrt [4]{a+b x^2}} \, dx}{4 c d^2}-\frac{((b c-a d) (5 b c+2 a d)) \int \frac{1}{\sqrt [4]{a+b x^2} \left (c+d x^2\right )} \, dx}{4 c d^2}\\ &=-\frac{(b c-a d) x \left (a+b x^2\right )^{3/4}}{2 c d \left (c+d x^2\right )}-\frac{\left ((b c-a d) (5 b c+2 a d) \sqrt{-\frac{b x^2}{a}}\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{1-\frac{x^4}{a}} \left (b c-a d+d x^4\right )} \, dx,x,\sqrt [4]{a+b x^2}\right )}{2 c d^2 x}+\frac{\left (b (5 b c-a d) \sqrt [4]{1+\frac{b x^2}{a}}\right ) \int \frac{1}{\sqrt [4]{1+\frac{b x^2}{a}}} \, dx}{4 c d^2 \sqrt [4]{a+b x^2}}\\ &=\frac{b (5 b c-a d) x}{2 c d^2 \sqrt [4]{a+b x^2}}-\frac{(b c-a d) x \left (a+b x^2\right )^{3/4}}{2 c d \left (c+d x^2\right )}+\frac{\left ((b c-a d) (5 b c+2 a d) \sqrt{-\frac{b x^2}{a}}\right ) \operatorname{Subst}\left (\int \frac{1}{\left (\sqrt{-b c+a d}-\sqrt{d} x^2\right ) \sqrt{1-\frac{x^4}{a}}} \, dx,x,\sqrt [4]{a+b x^2}\right )}{4 c d^{5/2} x}-\frac{\left ((b c-a d) (5 b c+2 a d) \sqrt{-\frac{b x^2}{a}}\right ) \operatorname{Subst}\left (\int \frac{1}{\left (\sqrt{-b c+a d}+\sqrt{d} x^2\right ) \sqrt{1-\frac{x^4}{a}}} \, dx,x,\sqrt [4]{a+b x^2}\right )}{4 c d^{5/2} x}-\frac{\left (b (5 b c-a d) \sqrt [4]{1+\frac{b x^2}{a}}\right ) \int \frac{1}{\left (1+\frac{b x^2}{a}\right )^{5/4}} \, dx}{4 c d^2 \sqrt [4]{a+b x^2}}\\ &=\frac{b (5 b c-a d) x}{2 c d^2 \sqrt [4]{a+b x^2}}-\frac{(b c-a d) x \left (a+b x^2\right )^{3/4}}{2 c d \left (c+d x^2\right )}-\frac{\sqrt{a} \sqrt{b} (5 b c-a d) \sqrt [4]{1+\frac{b x^2}{a}} E\left (\left .\frac{1}{2} \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )\right |2\right )}{2 c d^2 \sqrt [4]{a+b x^2}}+\frac{\sqrt [4]{a} \sqrt{-b c+a d} (5 b c+2 a d) \sqrt{-\frac{b x^2}{a}} \Pi \left (-\frac{\sqrt{a} \sqrt{d}}{\sqrt{-b c+a d}};\left .\sin ^{-1}\left (\frac{\sqrt [4]{a+b x^2}}{\sqrt [4]{a}}\right )\right |-1\right )}{4 c d^{5/2} x}-\frac{\sqrt [4]{a} \sqrt{-b c+a d} (5 b c+2 a d) \sqrt{-\frac{b x^2}{a}} \Pi \left (\frac{\sqrt{a} \sqrt{d}}{\sqrt{-b c+a d}};\left .\sin ^{-1}\left (\frac{\sqrt [4]{a+b x^2}}{\sqrt [4]{a}}\right )\right |-1\right )}{4 c d^{5/2} x}\\ \end{align*}
Mathematica [C] time = 0.335801, size = 340, normalized size = 1. \[ \frac{x \left (\frac{6 c \left (x^2 \left (a+b x^2\right ) (a d-b c) \left (4 a d F_1\left (\frac{3}{2};\frac{1}{4},2;\frac{5}{2};-\frac{b x^2}{a},-\frac{d x^2}{c}\right )+b c F_1\left (\frac{3}{2};\frac{5}{4},1;\frac{5}{2};-\frac{b x^2}{a},-\frac{d x^2}{c}\right )\right )-6 a c \left (2 a^2 d+a b d x^2-b^2 c x^2\right ) F_1\left (\frac{1}{2};\frac{1}{4},1;\frac{3}{2};-\frac{b x^2}{a},-\frac{d x^2}{c}\right )\right )}{\left (c+d x^2\right ) \left (x^2 \left (4 a d F_1\left (\frac{3}{2};\frac{1}{4},2;\frac{5}{2};-\frac{b x^2}{a},-\frac{d x^2}{c}\right )+b c F_1\left (\frac{3}{2};\frac{5}{4},1;\frac{5}{2};-\frac{b x^2}{a},-\frac{d x^2}{c}\right )\right )-6 a c F_1\left (\frac{1}{2};\frac{1}{4},1;\frac{3}{2};-\frac{b x^2}{a},-\frac{d x^2}{c}\right )\right )}-b x^2 \sqrt [4]{\frac{b x^2}{a}+1} (a d-5 b c) F_1\left (\frac{3}{2};\frac{1}{4},1;\frac{5}{2};-\frac{b x^2}{a},-\frac{d x^2}{c}\right )\right )}{12 c^2 d \sqrt [4]{a+b x^2}} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.049, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{ \left ( d{x}^{2}+c \right ) ^{2}} \left ( b{x}^{2}+a \right ) ^{{\frac{7}{4}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x^{2} + a\right )}^{\frac{7}{4}}}{{\left (d x^{2} + c\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b x^{2}\right )^{\frac{7}{4}}}{\left (c + d x^{2}\right )^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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